168k views
7 votes
What will the pressure be if 89.9 moles of argon are contained in a 12.0 L cylinder that is pressurized at a temperature of 300 K?

1 Answer

6 votes
  • P=nRT/V
  • p=89.9(8.314)(12)/300
  • P=8969.14/300
  • P=29.89atm
  • P=29.9atm

Done!