89.3k views
2 votes
What is the strength of the electric field 0.020 m from a 12 uc charge?

5.4 x 106 N/C

O 2.7 x 108 N/C

O 5.4 x 1012 N/C

O 2.7 x 1014 N/C

User KolA
by
5.2k points

2 Answers

4 votes

Answer:

X: positive

Y: negative

Step-by-step explanation:

An electric field around two charged objects is shown.

Two spheres next to each other. Vectors perpendicular to each surface spread out and go to the other charge. The vectors are from the charge on the left, labeled X, and to the other charge, labeled Y. The vectors on the opposite sides of the charges are not bent.

What are the charges of objects X and Y?

X: negative

Y: positive

X: positive

Y: positive

X: negative

Y: negative

X: positive

Y: negative

User Nick Savage
by
5.1k points
3 votes

Answer:

Option B is correct.

Step-by-step explanation:

Given the charge, Q = 12uC

Now convert the uC into C = 5*10^-6 C

Given, d = 0.020 m

Now use the below formula:

E = K*Q/d^2

Now insert all the values in the above formula and then solve.

E = (9 ×10^9) × (12×10^-6) / (0.020)^2

E = 2.7 ×10^8 N/C

Therefore option B is correct.

User Quynh
by
5.3k points