Answer:
10.65 m/s
Step-by-step explanation:
Given that an Olympic diver is on a diving platform 5.70 m above the water. To start her dive, she runs off of the platform with a speed of 1.27 m/s in the horizontal direction.
Her initial velocity U = 1.27 m/s
The height H = 5.7 m
The final velocity V will be calculated by using the formula;
V^2 = U^2 + 2gH
Substitute U, g and H into the formula
V^2 = 1.27^2 + 2 × 9.8 × 5.7
V^2 = 1.6129 + 111.72
V^2 = 113.33
V = sqrt ( 113.33)
V = 10.65 m/s
Therefore, the diver's speed, in m/s, just before she enters the water is 10.65