Answer: the probability that the 130 orders can be filled without reordering components is 0.004957
Explanation:
The probability that 130 orders can be filled without reordering components if the manufacturer stocks 130 component
so let x = 0
given that;
size n = 130
p = 4% = 0.04
the probability is
p(x=0) = [130] [0.04]^0 [1 - 0.04]^130-0
[ 0 ]
p(x=0) = [1] [1] [0.004957]
p(x=0) = 0.004957
therefore the probability that the 130 orders can be filled without reordering components is 0.004957