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A 860 kΩ resistor has 34 μA of current. What is the supply voltage for this electric circuit?

I already know the answer, just looking for a second opinion.
If you do not know the equation is V=I*R

PLEASE DO NOT ANSWER IF YOU DO NOT KNOW IT

User Ning Chen
by
4.6k points

2 Answers

5 votes

Step-by-step explanation:

first changing kilo ohm to ohm

860000 = 860 kΩ

and change 34 micro ampare to ampare

34 μA=3.4×10^-5

recalling the equation V=I*R

V= 3.4×10^-5×860000

v=29.24

User Jxadro
by
3.8k points
4 votes

Answer:

v=IR

V= 860 x 10^3 x 34 x 10^-6

V=29240 x 10^-3

V=29.24 V

User CharliePrynn
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4.1k points