Question

Differentiate y=(sinx)(3x^2) please help please !

Answer 1

6xsinx + 3x²cosx

Explanation:

Differentiate using the product rule

Given y = f(x)(g(x) , then

`(dy)/(dx)` = f(x)g'(x) + g(x)f'(x)

Here f(x) = sinx ⇒ f'(x) = cosx

g(x) = 3x² ⇒ g'(x) = 6x

Thus

`(dy)/(dx)` = 6xsinx + 3x²cosx