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Differentiate y=(sinx)(3x^2) please help please !

User Pattmatt
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1 Answer

5 votes

Answer:

6xsinx + 3x²cosx

Explanation:

Differentiate using the product rule

Given y = f(x)(g(x) , then


(dy)/(dx) = f(x)g'(x) + g(x)f'(x)

Here f(x) = sinx ⇒ f'(x) = cosx

g(x) = 3x² ⇒ g'(x) = 6x

Thus


(dy)/(dx) = 6xsinx + 3x²cosx

User Dvdrtrgn
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