Answer:
Probability that a random veteran will have been exposed to agent orange is 0.4667
Explanation:
P(exposed to agent cancer and develop cancer) = 0.35
P(develop cancer given he is already exposed to agent orange) = 0.75
P(is exposed to agent cancer) = ?
P(A given B) = P(A and B)/P(B),
P(develop cancer | exposed to agent orange) = P(develop cancer and exposed to agent orange)/P(exposed to agent orange)
0.75 = 0.35/P(exposed to agent orange)
P(exposed to agent orange) = 0.35/0.75
P(exposed to agent orange) = 0.4667