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M angle PQS= 3x; m angle SQR=5x-20
Find x

1 Answer

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Let as consider the complete ques is : Ray QS bisects ∠PQR. Solve for x and find m∠PQR. m∠PQS = 3x ; m∠SQR = 5x-20.

Given:

Ray QS bisects ∠PQR.

m∠PQS = 3x

m∠SQR = 5x-20

To find:

The value of x and m∠PQR

Solution:

Ray QS bisects ∠PQR. So,


m\angle PQS=m\angle SQR


3x=5x-20


3x-5x=-20


-2x=-20


x=10

The value of x is 10.

Now,


m\angle PQR=m\angle PQS+m\angle SQR


m\angle PQR=3x+5x-20


m\angle PQR=8x-20

Put x=10,


m\angle PQR=8(10)-20


m\angle PQR=80-20


m\angle PQR=60

Therefore, the m∠PQR is 60 degrees.

User Jiho Choi
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