Question

F(x)=-2x^2 -5x+1

H(x)=3(x+3)^2-11

H(f(-1))=?

A.132
B. 136
C.140
D.144

Answer 1

B

Explanation:

So we have the two functions:

`f(x)=-2x^2-5x+1\text{ and } h(x)=3(x+3)^2-11`

And we want to find:

`h(f(-1))`

So, find f(-1) first. Substitute -1 into f(x):

`f(-1)=-2(-1)^2-5(-1)+1`

Square:

`f(-1)=-2(1)-5(-1)+1`

Multiply:

`f(-1)=-2+5+1`

Add:

`f(-1)=4`

Now, substitute this into h(f(-1)):

`h(f(-1))=h(4)`

So, substitute 4 into h(x):

`h(4)=3(4+3)^2-11`

Add:

`h(4)=3(7)^2-11`

Square:

`h(4)=3(49)-11`

Multiply:

`h(4)=147-11`

Subtract:

`h(4)=136`

So, our answer is B.

And we're done!