Question

In a tug of war, team A is pulling the rope with a force of 60N towards the right and team B also applies 60N towards the left, what is the net force?

Answer 1

`f_n_e_t=0`

Step-by-step explanation:

`f_1+f_2=f_n_e_t`

because there are two different forces in different directions (left: negative, right: positive, down: negative, up: positive) so 60N left will be negative, and 60N right will be positive:

`60+(-60)=0`

when two same forces apllied then the net force is zero.