Answer:
see below
Explanation:
given:
LCM(a,b) = 20160, a=60
find:
smallest possible value of b
solution;
60, b = 20,160
b = 20,160 / 60
b = 336
60 x 336 = 20,160
= 2⁶ x 3² x 5 x 7
= (2² x 3 x 5) x (2⁴ x 3 x 7)
= (60) x (336)
LCM(60,336) = 1680
consider the 2² x 3 to get the prime number:
= 336 x 12
= 4032
therefore,
LCM(60,4032) = 20160