Question

H=vt+1/2gt^2 solving for G
GIVING BRAINLISEST

Answer 1

g =
`(2(h - vt))/(t^2)`

Explanation:

Given

h = vt +
`(1)/(2)` gt² ( subtract vt from both sides )

h - vt =
`(1)/(2)` gt² ( multiply both sides by 2 to clear the fraction )

2(h - vt) = gt² ( divide both sides by t² )

`(2(h-vt))/(t^2)` = g

Answer 2

`\displaystyle g = (2(h-vt))/(t^2)`

Explanation:

We are given the equation:

`\displaystyle h = vt+(1)/(2)gt^2`

And we want to solve for g, the acceleration due to gravity.

Proceed with algebra:

`\displaystyle \begin{aligned} h & = vt + (1)/(2)gt^2 \\ \\ h - vt & = (1)/(2)gt^2 \\ \\ gt^2& = 2(h-vt) \\ \\ g &= (2(h-vt))/(t^2)\end{aligned}`

In conclusion:

`\displaystyle g = (2(h-vt))/(t^2)`