Question

2
If A=
4 3
find A1 using
elementary row operations.​

Answer 1

Answer:
`A^(-1)=\left[\begin{array}{cc}(3)/(2)&-(1)/(2)\\-2&1\end{array}\right]`

Explanation:

`\left[\begin{array}{cc}2&1\\4&3\end{array}\right]=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]`

`(1)/(2)Row\ 1\rightarrow\left[\begin{array}{cc}1&(1)/(2)\\4&3\end{array}\right]=\left[\begin{array}{cc}(1)/(2)&0\\0&1\end{array}\right]`

`Row\ 2 -4 \ Row\ 1\rightarrow \left[\begin{array}{cc}1&(1)/(2)\\0&1\end{array}\right]=\left[\begin{array}{cc}(1)/(2)&0\\-2&1\end{array}\right]`

`Row\ 1-(1)/(2)\ Row\ 2 \rightarrow \left[\begin{array}{cc}1&0\\0&1\end{array}\right]=\left[\begin{array}{cc}(3)/(2)&-(1)/(2)\\-2&1\end{array}\right]`