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What is the temperature of 0,80 mol of a gas stored in a 275 mL cylinder at 175 kPa?

1 Answer

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Answer:

First, let's express pressure P in Pa and volume V in m3:

⇒P=175 kPa

⇒P=1.75×105 Pa

and

⇒V=275 ml

⇒V=2.75×10−4 m3

Then, let's solve the ideal gas law PV=nRT for temperature T:

⇒PV=nRT

⇒T=PVnR

Substituting the appropriate values into the equation:

⇒T=1.75×105×2.75×10−40.80×8.314 K

⇒T=48.1256.6512 K

∴T≈7.24 K

Therefore, the temperature is around 7.24 K.

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