Question

If a bullet with an acceleration of 1.5 m/s2 takes 2 seconds to leave the muzzle of a rifle (starts at rest), what was the length of the rifles barrel?

Answer 1

The length is
`D  =3 \  m`

Step-by-step explanation:

The velocity of the bullet is mathematically evaluated as

`v  =  a * t`

=>
`v  = 1.5 * 2`

=>
`v  = 3 \  m/s`

Now from kinematic equation

`v^2  =  u^2 + 2* a  *  D`

Here D is the length of the barrel and u = 0 m/s

So

`3^2  =  0 + 2* 1.5  *  D`

`D  = (9)/(3)`

`D  =3 \  m`