If the perimeter of a square is 8√2, find the area of the square

Question

asked Jan 10, 2021 140k views

1 Answer

Dotnetpickles · Answer 1 · 2021-01-16T23:46:12+0000

Answer:

Area=128

Explanation:

p=8
√(2)

A=p^2

put value of p

A= (8
√(2) )power2

A= (8^2*
√(2) ^2)

A=64 * 2 (square root of 2 will be cancel by power 2)

A= 128