Question

If the perimeter of a square is 8√2, find the area of the square

Answer 1

Area=128

Explanation:

p=8
`√(2)`

A=p^2

put value of p

A= (8
`√(2)`)power2

A= (8^2*
`√(2)`^2)

A=64 * 2 (square root of 2 will be cancel by power 2)

A= 128