Answer:
The boy's age is 8, the younger brother's age is 4.
- What we know is that the first brother has to be 8, because the equation given is x = y(younger brother) + 8
- Now we must solve the equation based off of this.
![x = y + 8\\x(likely~8?) + 4 = 2 * (y + 4)](https://img.qammunity.org/2023/formulas/mathematics/high-school/h82mecfh66st3ptbagna9qk3zbvb4fopjd.png)
- Hmm. What would the product of twice the sum of the younger brother's age be?
![x = 2*y](https://img.qammunity.org/2023/formulas/mathematics/high-school/b7ejbtwoa8vag9iwbgafp49ohyp0fn2syb.png)
- If we have already found out that the older brother's age is currently 8, we know that that 8 + 4 is 12, and in that case, the 2 must be the current age apart the brothers are, 2 years. And that would mean the younger brother is 4. Let's finish the equation.
To find the younger brother's age using the given values...
![8 + 4 = 12](https://img.qammunity.org/2023/formulas/mathematics/high-school/1n7mekt9sdhvof9al412792cattdzyfo56.png)
That said, everything matches up with the equation. The first brother is twice the age of his younger brother.