Question

How many gallons of a 60% antifreeze solution must be mixed with 70 gallons of 20% antifreeze to get a misture that is 50% antifreeze? Use the she-step method

Answer 1

210 gaL 60 % Antifreeze II

Explanation:

In the problem, there are two types of antifreeze

antifreeze I and

antifreeze II

antifreeeze I 20 ----70 gal

Antifreeze II 60 ----- x gal

Total 50 ---------------- (70 + x ) gal

20*70+60*x=50(70+x)

1400+60x=3500+50x

60x-50x=3500-1400

10x=2100

x= 210

x=210 gaL 60 % Antifreeze II