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What is the equation of the line that is parallel to y = 2/3x+ 4 and passes through

the point (-7, 1)?

User Typo
by
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1 Answer

6 votes

Answer:

The answer is


y = (2)/(3) x + (17)/(3)

Explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find the equation of the parallel line we must first find the slope of the original line

The original line is y = ⅔x + 4

Comparing with the general equation above

Slope = 2/3

Since the lines are parallel their slope are also the same

Slope of parallel line = 2/3

Equation of the line using point (-7 , 1) and slope 2/3 is


y - 1 = (2)/(3) (x + 7) \\ y - 1 = (2)/(3) x + (14)/(3) \\ y = (2)/(3) x + (14)/(3) + 1

We have the final answer as


y = (2)/(3) x + (17)/(3)

Hope this helps you

User Bob Mc
by
7.6k points

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