Question

What is the equation of the line that is parallel to y = 2/3x+ 4 and passes through

the point (-7, 1)?

Answer 1

The answer is

`y = (2)/(3) x + (17)/(3)`

Explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find the equation of the parallel line we must first find the slope of the original line

The original line is y = ⅔x + 4

Comparing with the general equation above

Slope = 2/3

Since the lines are parallel their slope are also the same

Slope of parallel line = 2/3

Equation of the line using point (-7 , 1) and slope 2/3 is

`y - 1 = (2)/(3) (x + 7) \\ y - 1 = (2)/(3) x + (14)/(3) \\ y = (2)/(3) x + (14)/(3) + 1`

We have the final answer as

`y = (2)/(3) x + (17)/(3)`

Hope this helps you