Solve for y 2x+y-3z=5

Question

asked Jan 20, 2023 106k views

2 Answers

Yodacheese · Answer 1 · 2023-01-23T00:04:55+0000

Answer:

Option A

Explanation:

Since the "y" variable is inside a root, we need to square both sides of the equation to open the root and solve for y.

When squaring both sides, we get;

$\implies √(2x + y - 3z) = 5$

$\implies(√(2x + y - 3z))^(2) = 5^(2)$

$\implies2x + y - 3z = 25$

Now, simply isolate the y-variable to determine its value. This can be done by subtracting 2x on both sides of the equation.

$\implies2x + y - 3z = 25$

$\implies2x + y - 3z - 2x = 25 - 2x$

$\implies y - 3z = 25 - 2x$

Now, add 3z both sides of the equation to further isolate the y-variable.

$\implies y - 3z + 3z = 25 - 2x + 3z$

$\implies y = 25 - 2x + 3z$

Therefore, Option A is correct.

Tawanna · Answer 2 · 2023-01-24T07:54:19+0000

Answer:

Explanation:

Isolate the term of x and y from one side of the equation.

To solve:

$\Longrightarrow: \sf{√(2x+y-3z)=5}$

First, you have to subtract by 2x-3z from both sides.

$\Longrightarrow: \sf{2x+y-3z-\left(2x-3z\right)=25-\left(2x-3z\right)}}$

Solve.

$\Longrightarrow: \boxed{\sf{y=25-2x+3z}}}$

I hope this helps, let me know if you have any questions.