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Subtract. (8y + y2 + 7y + 9) - (y2 + 3)​

User JamesOR
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1 Answer

5 votes

Answer:


\boxed{ \bold{ \huge{ \boxed{ \sf{15y + 6}}}}}

Explanation:


\sf{(8y + {y}^(2) + 7y + 9) - ( {y}^(2) + 3)}

When there is a ( - ) in front of an expression in parentheses, change the sign of each term


\dashrightarrow \sf{8y + {y}^(2) + 7y + 9 - {y}^(2) - 3}

Since two opposites add up to zero, remove them from the expression


\dashrightarrow{ \sf{8y + 7y + 9 - 3}}

Add the like terms : 8y and 7y


\dashrightarrow{ \sf{15y + 9 - 3}}

The negative and positive integers are always subtracted but posses the sign of the bigger integer


\longrightarrow{ \sf{15y + 6}}

Hope I helped!

Best regards! :D

User Fabian Giesen
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