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Solve 6x^3-7x^2-5x=0

User Iwazovsky
by
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1 Answer

5 votes

Factor the x out first:

x(6x^2 - 7x - 5) = 0

Then factor the quadratic expression in the parenthesis:

x(2x + 1)(3x - 5) = 0

x = -1/2, 0, 5/3

User Steven Doggart
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