Answer:
Ok, if we start with a number n, then we can write the consecutive numbers of n as:
n + 1
n + 2
n + 3..
etc.
Now, suppose that we have an integer x, and we want to write it as a sum of consecutive numbers.
There is a really trivial way.
We know that x + 0 = x.
now, we can write:
0 = (x - 1) + (x - 2) + ... + 1 + 0 + (-1) + (-2) + ..... + (-x + 2) + (x - 1)
Then we wrote zero as a sum of consecutive numbers.
Now we can write:
x = x + 0 = x + (x - 1) + (x - 2) + .... + 1 + 0 - 1 - 2 - ... - (x - 1) = x
Then we show that for any integer x, we can write it as a sum of consecutive integers.
Then it must work for all the integers x, then we prove that all the integers can be written as a sum of consecutive integers.