Question

g A very early, simple satellite consisted of an inflated spherical aluminum balloon 38 m in diameter and of mass 22 kg. Suppose a meteor having a mass of 21 kg passes within 8.0 m of the surface of the satellite. What is the magnitude of the gravitational force on the meteor from the satellite at the closest approach?

Answer 1

6.37*10^-13 N

Step-by-step explanation:

Given that

We r = 38/2 = 14 m

m1 = 22kg

m2 = 21 kg

so we can say that distance between center of the satellite and meteor,

d = r + h

= 14 + 8

= 22m

So the gravitational force on the meteor, is

F = G x m1 x m2/d²

= 6.67*10^-11 x 21 *22/22²

= 6.37*10^-13 N