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The minimum fresh air requirement of a residential building is specified to be 0.35 air changes per hour (ASHRAE, Standard 62, 1989). That is, 35 percent of the entire air contained in a residence should be replaced by fresh outdoor air every hour. If the ventilation requirement of a 2.7-m-high, 200-m2 residence is to be met entirely by a fan, determine the flow capacity in L/min of the fan

User Panepeter
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1 Answer

5 votes

Answer:

3150 L/min

Step-by-step explanation:

The volume of the room is the product of the height of the room and its area. It is given as:

Volume (V) = height (h) × Area (A)

V = h × A

Height = 2.7 m, Area = 200 m². Hence:

V = h × A = 2.7 × 200 = 540 m³

The flow capacity (
\dot {V}) is given by


\dot {V}=ACH*Volume\ of\ room

ACH = air changes per hour = 0.35


\dot {V}=ACH*Volume\ of\ room\\\\\dot {V}=0.35*540\\\\\dot {V}=189\ m^3/h

But 1 m³ = 1000 L, 1 hr = 60 min


\dot{V}=189\ m^3/h=(189\ m^3*(1000\ L)/(1\ m^3) )/(1\ h*(60\ min)/(1\ h) ) =3150\ L/min\\\\\dot{V}=3150 \ L/min

User Jevaughn
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