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Find the number of real number solutions for the equation.

x2 + 0x − 1 = 0


0


2


1

Find the number of real number solutions for the equation. x2 + 0x − 1 = 0 0 2 1-example-1

2 Answers

7 votes

Answer: the answer is 0

User Brenlla
by
3.0k points
4 votes

Answer:

x = ±1

Explanation:

x² + 0x -1 = 0

x²- 1 = 0

x² = 1

x = ±1

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check

1² + 0x - 1 = 0

1 - 1 = 0

User Siddhivinayak
by
3.2k points