Answer:
(-2, 1) and (6, 1)
Explanation:
The standard form equations for a hyperbola are ...
![((x-h)^2)/(a^2)-((y-k)^2)/(b^2) = 1 \\\\((y-k)^2)/(a^2)-((x-h)^2)/(b^2) = 1](https://img.qammunity.org/2023/formulas/mathematics/college/bvtdydw6jvgjuarcj1ie9xgyz6jaq9t13m.png)
The first form opens horizontally; the second opens vertically. Further, the center-focus distance 'c' is given by ...
![c^2 = a^2 +b^2 \qquad\text{$c$ = distance from center to focus}](https://img.qammunity.org/2023/formulas/mathematics/college/plyejtj6ih769709o9d3f57p1qqnzp3ue9.png)
The attached figure illustrates the relation between the various parameters and the features of the hyperbola.
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7.
Using the above information and the information in the first attachment, we find ...
(h, k) = (2, 1)
a = 4, b = 2
The vertices are (h±a, k), so are (2±4, 1) = (-2, 1) and (6, 1).
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The second attachment illustrates the hyperbola and its vertices.