Answer:
The voltage gain is 2.07.
Step-by-step explanation:
Given that,
Resistance
![R_(1)=14\ k\Omega](https://img.qammunity.org/2021/formulas/engineering/college/tozm9z88w90hfsyeeoieaxe0w2835dv3qs.png)
Resistance
![R_(2)=13\ k\Omega](https://img.qammunity.org/2021/formulas/engineering/college/zxbo72wrfkvqagp90z935shz16irvvmltg.png)
We need to calculate the voltage gain
Using formula of voltage source
![V_(s)=(V_(o)* R_(2))/(R_(1)+R_(2))](https://img.qammunity.org/2021/formulas/engineering/college/xvc04fi9qlxk20ag5jmrra7bu7kt9wi5te.png)
![(V_(o))/(V_(s))=(R_(1)+R_(2))/(R_(2))](https://img.qammunity.org/2021/formulas/engineering/college/n3krzyaptu4spn5989lexpixznsgo7yoap.png)
Where,
= first resistance
=second resistance
= source voltage
= output voltage
Put the value into the formula
![(V_(o))/(V_(s))=(14+13)/(13)](https://img.qammunity.org/2021/formulas/engineering/college/x8d4xvu6velnvclfz77z2nk8ycq4mpqdco.png)
![(V_(o))/(V_(s))=2.07](https://img.qammunity.org/2021/formulas/engineering/college/deye32gt18qr5jfnh3f56xhdgl9ca8sw4t.png)
Hence, The voltage gain is 2.07