Question

The length, width, and height of an Aluminum block are 1.15 cm, 1.15 cm, and 2 cm respectively. The mass of the block is 6.8 grams. What is the density of the Aluminum block?

Answer 1

`Density = 2570.89\ kg/m^3`

Step-by-step explanation:

Given

Mass = 6.8 g

Dimension = 1.15 cm by 1.15 cm by 2 cm

Required

Density is calculated using the following formula:

`Density = (Mass)/(Volume)`

Start by converting mass from grams to kilograms;

`Mass = 6.8g`

`Mass = 6.8 * 0.001kg`

`Mass = 0.0068kg`

Volume is then calculated as follows;

`Volume = 1.15cm * 1.15cm * 2cm`

Convert cm to metres

`Volume = 0.0115m* 0.0115m * 0.02m`

`Volume = 0.000002645m^3`

Substitute these values in the above formula;

`Density = (Mass)/(Volume)`

`Density = (0.0068)/(0.000002645)`

`Density = 2570.88846881kg/m^3`

`Density = 2570.89\ kg/m^3` (Approximated)