Question

determine the minimum and maximum angles to the nearest tenth of a degree that a pipe can make with the horizontal. the minimum angle being 1/4 inch the maximum angle being 1/2 inch. HELP PLEASE

Answer 1

Given :

A pipe can make with the horizontal. the minimum angle being 1/4 inch the maximum angle being 1/2 inch .

To Find :

The minimum and maximum angles to the nearest tenth of a degree that a pipe can make with the horizontal.

Solution :

Angle
`\theta` is given by :

`tan\ \theta=(opp)/(adj)`

Now , minimum angle is given by :

`tan\ \theta_(min)=((1)/(4))/(12)=0.02\\\\\theta_(min)=tan^(-1)(0.02)\\\\\theta_(min)=1.146^o`

For maximum angle :

`tan\ \theta_(max)=((1)/(2))/(12)=0.04\\\\\theta_(max)=tan^(-1)(0.04)\\\\\theta_(max)=2.291^o`

Therefore , minimum and maximum angle is 1.146° and 2.291° respectively .

Hence , this is the required solution .