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Burning of fuel in air is called combustion. CH4(g) + 2O2(g) --------- CO2 (g)+ 2H2O(l) a) Calculate the heat of reaction for the above reaction by using the following bond energies . (3 Marks) C-H single bond is 412 kJ , O=O double bond is 496 kJ, C=O double bond is 743 kJ, H-O single bond is 463 kJ b) Draw the energy profile diagram for the above reaction .On your diagram label the • Products, Reactants • enthalpy for the reaction • activation energy, Ea.

User Nwhaught
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Answer:

Step-by-step explanation:

ΔH = ∑ BREAKING BONDS + ∑ GREATING NEW BONDS

=( 4×412 + 2×496) _ ( 2×743 + 4×463)

= 2640 KJ _ 3338 KJ = - 698 KJ/Mole

exothermic reaction

b) CH4 + O2 are the reactant

CO2 +H2O are the product

Burning of fuel in air is called combustion. CH4(g) + 2O2(g) --------- CO2 (g)+ 2H-example-1
User Mobiledaemon
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