Question

Hello if you could kindly pls help

Answer 1

A=4x^2+24x

Explanation:

Plug 8x in for base and x+ 6 in for Hight

A=1/2(8x)(x+6)

Now multiply 8x and x+6

(8x)(x+6)=8x^2+48x

Dived by 2

(8x^2+48x)/2

A=4x^2+24x

Hope this helps!

: )

Answer 2

`\boxed{ \boxed{ \bf{Given : }}}`

• Base,b = 8x

• Height,h = x + 6

`\boxed{ \boxed{ \bf{To \: be \: calculated : }}}`

Calculate the area of the triangle in term of x.

`\boxed{ \boxed{ \bf{Solution : }}}`

We know that,

`\sf \: Area \: of \: triangle = (1)/(2) * b * h`

`\sf \rightarrow \: Area \: of \: triangle \: = (1)/(2) * 8x * (x + 6)`

`\sf \rightarrow \: Area \: of \: triangle = \frac{8 {x}^(2) + 48x }{2}`

`\sf \rightarrow \: Area \: of \: triangle = \frac{ \cancel2(4 {x}^(2) + 24x) }{ \cancel2}`

`\sf \rightarrow \: Area \: of \: triangle = 4 {x}^(2) + 24x`

Hence,the area of triangle is 4x² + 24x units.