Question

[2 Marks] What is the pressure in atm of 16.7 mol helium that occupies a volume of 7.2 L at a temperature of 279 K?

Answer 1

53.13atm

Step-by-step explanation:

PV=nRT

P=nRT/V

= 16.7mol*0.0821LatmK^-1mol^-1*279K/7.2L

=53.13atm