Question

46.

Find the perimeter of a rectangle with a length of 10 feet and width of 6 feet.
47. Find the area of the rectangle in problem number 46.

Answer 1

46. we do 10+6+10+6= 32 feet

47. 10 x 6= 60 feet squared (^2)

Answer 2

46. 10+10+6+6=32

47. 10×6=60

Explanation:

46. the formula the perimeter is length plus width, is this case 10+6. but that would only be 2 sides so you have to times that by 2... (10+6)×2

47. area equals length times width so in this case 10×6=60