Final answer:
To solve the problem, set up a system of equations and solve it using the elimination method. The number of large pictures sold is 6 and the number of small pictures sold is 10.
Step-by-step explanation:
To solve this problem, we can set up a system of equations. Let's denote the number of large pictures as 'L' and the number of small pictures as 'S'. From the given information, we can form the following equations:
- L + S = 16 (equation 1)
- 25L + 20S = 350 (equation 2)
To solve this system of equations, we can either use substitution or elimination method. Let's solve it using the elimination method.
- Multiply equation 1 by 20 to make the coefficients of S in both equations equal: 20L + 20S = 320 (equation 3)
- Subtract equation 3 from equation 2 to eliminate S: (25L + 20S) - (20L + 20S) = 350 - 320
- Simplify the equation: 5L = 30
- Divide both sides by 5: L = 6
- Substitute the value of L into equation 1 to solve for S: 6 + S = 16
- Simplify the equation: S = 10
Therefore, you sold 6 large pictures and 10 small pictures at the fair.