If h(x)=9+x², solve for x when h(x)=13

Question

asked Jan 9, 2021 165k views

2 Answers

Polyglot · Answer 1 · 2021-01-16T02:59:05+0000

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \bold{ \sf{x = 2}}}}}}$

Explanation:

Given, h(x) = 13

To find : value of x

$\sf{h(x) = 9 + {x}^(2) }$

$\longrightarrow{ \sf{13 = 9 + {x}^(2) }}$

Swap the sides of equation

$\longrightarrow{ \sf{9 + {x}^(2) = 13}}$

Move 9 to right hand side and change it's sign

$\longrightarrow{ \sf{ {x}^(2) = 13 - 9}}$

Subtract 9 from 13

$\longrightarrow{ \sf{ {x}^(2) = 4}}$

$\longrightarrow{ \sf{ \sqrt{ {x}^(2) } = √(4) }}$

$\longrightarrow{ \sf{x = \: \sqrt{ {2}^{{2}} }}}$

$\longrightarrow{ \sf{x = 2}}$

Hope I helped!

Best regards!