Question

If h(x)=9+x², solve for x when h(x)=13

Answer 1

I hope you got it. I have presented it clearly and stepwise.

Answer 2

`\boxed{ \bold{ \huge{ \boxed{ \bold{ \sf{x = 2}}}}}}`

Explanation:

Given, h(x) = 13

To find : value of x

`\sf{h(x) = 9 + {x}^(2) }`

`\longrightarrow{ \sf{13 = 9 + {x}^(2) }}`

Swap the sides of equation

`\longrightarrow{ \sf{9 + {x}^(2) = 13}}`

Move 9 to right hand side and change it's sign

`\longrightarrow{ \sf{ {x}^(2) = 13 - 9}}`

Subtract 9 from 13

`\longrightarrow{ \sf{ {x}^(2) = 4}}`

`\longrightarrow{ \sf{ \sqrt{ {x}^(2) } = √(4) }}`

`\longrightarrow{ \sf{x = \: \sqrt{ {2}^{{2}} }}}`

`\longrightarrow{ \sf{x = 2}}`

Hope I helped!

Best regards!