Question

Distance between (2,4)and(1,0)​

Answer 1

`\boxed{ \bold{ \huge{ \boxed{ \sf{ √(17) \: \: units}}}}}`

Step-by-step explanation:

Let the points be A and B

Let A ( 2 , 4 ) be ( x₁ , y₁ ) and B ( 1 , 0 ) be ( x₂ , y₂ )

Finding the distance between these points

`\boxed{ \sf{distance = \sqrt{ {(x2 - x1)}^(2) + {(y2 - y1)}^(2) } }}`

`\longrightarrow{ \sf{ \sqrt{ {(1 - 2)}^(2) + {(0 - 4)}^(2) } }}`

`\longrightarrow{ \sf{ \sqrt{ {( - 1)}^(2) + {( - 4)}^(2) } }}`

`\longrightarrow{ \sf{ √(1 + 16)}}`

`\longrightarrow{ \sf{ √(17) }}` units

Hope I helped!

Best regards! :D

Answer 2

By using distance formula

your answer is √17

Step-by-step explanation:

√(1-2)^2+(0-4)^2

√(-1)^2+(-4)^2

√1+16 = √17