Question

Find an equation of the line having the given slope and containing the given point. m=8 (-4,-3)

Answer 1

`y=8x+29`

Explanation:

Since we know the slope and a point, we can use the point-slope form.

The point-slope form is:

`y-y_1=m(x-x_1)`

Substitute 8 for m, and let (-4,-3) be x₁ and y₁, respectively. Thus:

`y-(-3)=8(x-(-4))`

Simplify:

`y+3=8(x+4)`

Distribute:

`y+3=8x+32`

Subtract 3 from both sides:

`y=8x+29`

And we're done!