Question

Plot a point C that divides the segment into the
ratio AC:AB= 3/4

Answer 1

Given :

A graph .

To Find :

A point C that divides the segment into the ratio AC:AB= 3/4 .

Solution :

From the graph we can see that point A and B are ( 1 , -2 ) and ( 5 , 6 ) respectively .

Now , we know point which divide a line segment with end point
`(x_1,y_1)` and
`(x_2,y_2)` in m : n is :

`x=(mx_2+nx_1)/(m+n)\ ,\ y=(my_2+ny_1)/(m+n)`

Putting all given values we get :

`x=(3(5)+4(1))/(3+4)\ ,\ y=(3(6)+4(-2))/(3+4)\\\\x=(19)/(7)\ ,\ y =(10)/(7)`

Therefore , point C is
`((19)/(7),(10)/(7))` .

Hence , this is the required solution .