Answer:
197.98g
Step-by-step explanation:
This question can be calculated using the formula: Q = mcΔT
Where Q= heat transfer
M= mass
C= specific capacity
ΔT= change in temperature
Heat from the copper metal is lost to the water when placed in it, hence, we have:
Q(water) = -Q(copper)
The final temperature of the water is equally to the final temperature of the copper= 22.87°C.
Hence, mcΔT (water) = (-) mcΔT (copper)
Note that, specific heat (C) of water and copper are 4.184 J/g°C and 0.385 J/g°C respectively.
Therefore;
= (m) (4.184) (22.87-21.65) = - {(35.41) (0.385) (22.87-97)}
= m × 4.184 × 1.22 = - {35.41 × 0.385 × -74.13)}
5.10448m = - {-1010.6031}
5.10448m = 1010.6031
m = 1010.6031 ÷ 5.10448
m = 197.98
Therefore, the mass of water copper was added to is 197.98g