Question

Find the value of x in the logarithmic equation below: 2log4 2=x+1

Answer 1

x = 0

Explanation:

Solve for x:

1 = x + 1

Hint: | Reverse the equality in 1 = x + 1 in order to isolate x to the left hand side.

1 = x + 1 is equivalent to x + 1 = 1:

x + 1 = 1

Hint: | Isolate terms with x to the left hand side.

Subtract 1 from both sides:

x + (1 - 1) = 1 - 1

Hint: | Look for the difference of two identical terms.

1 - 1 = 0:

x = 1 - 1

Hint: | Look for the difference of two identical terms.

1 - 1 = 0:

Answer: x = 0

Answer 2

`x=0`

Explanation:

So we have the equation:

`2\log_4{2}=x+1`

First, evaluate the logarithm. 4 to the what power is 2?

The square root of 4 or 4 to the 1/2 power is 2. Thus:

`2((1)/(2))=x+1`

Multiply:

`1=x+1`

Subtract 1 from both sides:

`0=x`

Flip:

`x=0`

So, the value of x is 0.

And we're done!