Answer:
The two numbers are 16 and 26.
Explanation:
We can solve this question using 2 simultaneous equations based on the given information from the question.
Let number 1 = x
Let number 2 = y
xy = 416 -> ( 1 )
x + y = 42 -> ( 2 )
We can use either substitution or elimination to solve simultaneous equations. For this question, we will use substitution as it is the easier and shorter option.
Make y the subject in ( 2 ):
x + y = 42 -> ( 2 )
y = 42 - x -> ( 3 )
Substitute ( 3 ) into ( 1 ):
xy = 416 -> ( 1 )
x ( 42 - x ) = 416
42x - x^2 = 416
-x^2 + 42x - 416 = 0
- [ x^2 - 42x + 416 ] = 0
- [ x^2 - 16x - 26x + 416 ] = 0
- [ x ( x - 16 ) - 26 ( x - 16 ) ] = 0
- ( x - 16 ) ( x - 26 ) = 0
x = 16 -> ( 4 ) , x = 26 -> ( 5 )
Substitute ( 4 ) into ( 3 ):
y = 42 - x -> ( 3 )
y = 42 - ( 16 )
y = 26
Substitute ( 5 ) into ( 3 ):
y = 42 - x -> ( 3 )
y = 42 - ( 26 )
y = 16
Therefore:
x = 16 , y = 26
x = 26 , y = 16
The two numbers are 16 and 26.