Question

In the chemical closet, you found an unlabeled vial with a solid piece of an unknown element inside (element Z) You decided to put it in the mass-spec to figure out its atomic mass. The results showed that it has two naturally occurring isotopes, Z-85, and Z-87. Z-85 has a natural abundance of 72.17% and a mass of 84 912 amu Z-87 has a natural abundance of 27 83% and a mass of 86 909 amu. Calculate the average atomic mass and determine the identity of mystery element Z

Answer 1

85.4678

It is Rubidium

Step-by-step explanation:

A natural abundance of 72.17% and a mass of 84 912 amu

A natural abundance of 27 83% and a mass of 86 909 amu.

Average atomic mass

= 84.912 x .7217 + 86.909 x .2783

= 61.28099+24.18677

= 85.46776

=85.4678

It is Rubidium .