Question

(2x - 3) + (1x + 2)
How do I solve it

Answer 1

(2x-3)=(1x+2)

We move all terms to the left:

(2x-3)-((1x+2))=0

We add all the numbers together, and all the variables

(2x-3)-((x+2))=0

We get rid of parentheses

2x-((x+2))-3=0

We calculate terms in parentheses: -((x+2)), so:

(x+2)

We get rid of parentheses

x+2

Back to the equation:

-(x+2)

We get rid of parentheses

2x-x-2-3=0

We add all the numbers together, and all the variables

x-5=0

We move all terms containing x to the left, all other terms to the right

x=5

Answer 2

3x - 1

Explanation:

Note that you are adding the parenthesis together. In this case, you can disregard the parenthesis. Combine like terms (terms with the same amount of variables):

2x + 1x - 3 + 2

(2x + 1x) + (-3 + 2)

3x + (-1)

3x - 1

3x - 1 is your answer.

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