102k views
0 votes
A six-sided fair die is rolled two times. Arrange the events in order from the event with the highest probability to the event with the lowest probability.

the probability of
getting the same
number on
each roll
the probability of
obtaining an odd
prime number
(excluding 1) on
each roll
the probability
that the difference
of the two
numbers is at
most 1
the probability
that the second
number is a
multiple of the
first number

2 Answers

10 votes

I think it should be 3>4>2>1

User Jeroen Mols
by
4.9k points
3 votes

The order of events from the highest to lowest probability is as follows:

The difference of the two numbers is at most 1 (11/36).

The second number is a multiple of the first number (7/36).

Getting the same number on each roll (1/6).

Obtaining an odd prime number on each roll (1/36).

Certainly, let's delve into a more detailed explanation of the probabilities:

The probability of obtaining an odd prime number (excluding 1) on each roll:

A six-sided die has odd prime numbers 3 and 5. Each of these has a probability of 1/6. The probability of obtaining an odd prime number on each roll is calculated by multiplying the individual probabilities, resulting in 1/36.

The probability of getting the same number on each roll:

Since there are six possible outcomes (1,1), (2,2), (3,3), (4,4), (5,5), and (6,6) out of 36 total outcomes, the probability of getting the same number on each roll is 6/36, which simplifies to 1/6.

The probability that the difference of the two numbers is at most 1:

Considering the pairs (1,1), (2,1), (2,2), (3,2), (3,3), (4,3), (4,4), (5,4), (5,5), (6,5), (6,6), there are 11 favorable outcomes out of 36 possible outcomes, resulting in a probability of 11/36.

The probability that the second number is a multiple of the first number:

Examining the pairs (2,1), (3,1), (4,1), (4,2), (5,1), (5,5), (6,1), there are 7 favorable outcomes out of 36, leading to a probability of 7/36.

User Iamchoosinganame
by
4.9k points