Question

If the period of a clock signal is 500 ps, the frequency is:_____

Answer 1

The frequency of the signal is 2 GHz

Step-by-step explanation:

Given;

period of the clock signal, T = 500 ps = 500 x 10⁻¹² s

the frequency of the signal is given by;

`F= (1)/(T)\\\\F = (1)/(500*10^(-12))\\\\F = 2*10^(9) \ Hz`

F = 2 GHz

Therefore, the frequency of the signal is 2 x 10⁹ Hz or 2 GHz